Q. 26 When the Newton-Raphson method is applied to solve the equation , the solution at the end of the first iteration with the initial value as x0 = 1.2 is
(A) -0.82
(B) 0.49
(C) 0.705
(D) 1.69
Answer:(C)
Explanation:
Q. 26 When the Newton-Raphson method is applied to solve the equation , the solution at the end of the first iteration with the initial value as x0 = 1.2 is
(A) -0.82
(B) 0.49
(C) 0.705
(D) 1.69
Answer:(C)
Explanation: