Q. 38 A binary symmetric channel (BSC) has a transition probability of 1/8. If the binary symbol X is such that P(X = 0) = 9/10, then the probability of error for an optimum receiver will be
(A) 7/80
(B) 63/80
(C) 9/10
(D) 1/10
Answer:
Explanation:
Not Required
