Gate CS-2004 Question Paper With Solutions

Q. 36 The order of an internal node in a B* tree index is the maximum number of

children it can have. Suppose that a child pointer takes 6 bytes, the search field

value takes 14 bytes., and the block size is 512 bytes. What is the order of the

internal node?

(A) 24

(B) 25

(C) 26

(D) 27

Answer: (C)

Explanation:

Gate CS-2004 Question Paper With Solutions

Learn More:   Gate EE-2013 Question Paper With Solutions

LEAVE A REPLY

Please enter your comment!
Please enter your name here