Total Power Calculator:
Enter the values of current, I(A), resistor one, R1(Ω), resistor two, R2(Ω) and resistor three, R3(Ω) to determine the value of Total power, Pt(W).
Total Power Formula:
Imagine a circuit with multiple components like resistors. Total power measured in watts (W), signifies the overall rate at which electrical energy is converted into other forms of energy (typically heat) within the entire circuit.
Higher current flow generally leads to higher power consumption in the circuit, as more electrical energy is being transferred per unit time.
Resistors oppose current flow. Higher resistance in a component translates to more energy conversion into heat within that component, contributing to the total power consumption.
When you connect a voltage source (like a battery) to a circuit, it creates a potential difference (voltage) that pushes electrical current (I) to flow through the components.
Each component with resistance (R) offers some opposition to the current flow. This opposition results in energy conversion. In resistors, this energy is primarily converted into heat, which is dissipated into the surrounding environment.
The formula essentially sums up the power dissipated in each individual component to determine the total power consumption of the entire circuit.
Total power, Pt(W) in watts is calculated by the sum of product of square of current, I(A) in amperes and resistor one, R1(Ω) in ohms and square of current, I(A) and resistor two, R2(Ω) and square of current, I(A) and resistor three, R3(Ω).
Total power, Pt(W) = I2(A) * R1(Ω) + I2(A) * R2(Ω) + I2(A) * R3(Ω)
Pt(W) = total power in watts, W.
I(A) = current in amperes, A.
R1(Ω), R2(Ω), R3(Ω) = resistance in ohms, Ω.
Total Power Calculation:
- A circuit consists of three resistors with resistances of 10 ohms (Ω), 20 ohms (Ω), and 30 ohms (Ω), respectively. If the current flowing through the circuit is 2 amperes (A), calculate the total power dissipated by the resistors.
Given: I(A) = 2A, R1(Ω) = 10 Ω, R2(Ω) = 20 Ω, R3(Ω) = 30 Ω.
Total power, Pt(W) = I2(A) * R1(Ω) + I2(A) * R2(Ω) + I2(A) * R3(Ω)
Pt(W) = 22 * 10 + 22 + 20 + 22 * 30
Pt(W) = 40 + 80 + 120
Pt(W) = 240W.
- A circuit has three resistors with resistances of 5 ohms (Ω), 15 ohms (Ω), and 25 ohms (Ω). The total power dissipated by the resistors is 180 watts (W). Calculate the current flowing through the circuit.
Given: Pt(W) = 180W, R1(Ω) = 5 Ω, R2(Ω) = 15 Ω, R3(Ω) = 25 Ω.
Total power, Pt(W) = I2(A) * R1(Ω) + I2(A) * R2(Ω) + I2(A) * R3(Ω)
180 = I2(A) * 5 + I2(A) * 15 + I2(A) * 25
180 = I2(A) * 45
I2(A) = 180 / 45
I(A) = √4
I(A) = 2A.