Tipping Force Calculator, Formula, Tipping Force Calculation

Tipping Force Calculator:

Enter the values of mass of the magnet, m­(kg), acceleration due to gravity, g(m/s2), angle of the magnet, x and distance, a and b to determine the value of tipping force, TF(N).

Enter Mass of the Magnet: kg
Enter Angle of the Magnet with the Horizontal:
Enter Distance: m
   
Result – Tipping Force: N

Tipping Force Formula:

Magnet tipping force is a measure of the force required to tip a magnet over an edge or pivot point, considering the gravitational pull on the magnet and the distribution of its mass relative to the pivot.

Tipping force, TF(N) in Newton is calculated by dividing the product of mass of the magnet, m­(kg) in kilograms, acceleration due to gravity, g(m/s2) in metres per second squared, angle of the magnet, x with the horizontal in degrees by the sum of distance, a and b in metres.

Tipping force, TF(N) = m­(kg) * g(m/s2) * cos(x) * b / (a+b)

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TF(N) = tipping force in Newton, N.

(kg) = mass of the magnet in kilogram, kg.

g(m/s2) = acceleration due to gravity (approximately 9.81m/s2 on the surface of the Earth)

x = angle of the magnet with the horizontal in degrees.

a,b = distance in metres, m.

Tipping Force Calculation:

  1. Consider a rectangular magnet with a mass of 2 kg. The magnet is placed on a surface where one edge serves as a pivot point. The distance from the pivot to the center of mass is 0.1m, and the total length of the magnet is 0.2m, making b = 0.1m. If the magnet makes an angle of 30° with the horizontal, calculate the tipping force.

Given: m­(kg) = 2kg, g(m/s2) = 9.81m/s2, x = 30degree = pi/6, a = 0.1m, b = 0.1m.

Tipping force, TF(N) = m­(kg) * g(m/s2) * cos(x) * b / (a+b)

TF(N) = 2 * 9.81 * cos(pi/6) * 0.1 / (0.1+0.1)

TF(N) = 2 * 9.81 * ((3)1/2/2) * 0.1 / 0.2

TF(N) = 1.701 * (3)1/2 / 2

TF(N) = 1.5N.

  1. The tipping force required to tip a magnet is 0.5 N, the distances from the pivot to the center of mass a is 0.1 metres, and from the center of mass to the edge opposite the pivot b is also 0.1 metres. The magnet is at an angle of 60degree with the horizontal. Calculate the mass of the magnet.
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Given: TF(N) = 0.5N, g(m/s2) = 9.81m/s2, x = 60degree = pi/3, a = 0.1m, b = 0.1m.

Tipping force, TF(N) = m­(kg) * g(m/s2) * cos(x) * b / (a+b)

(kg) = TF(N) * (a+b) / g(m/s2) * cos(x) * b

(kg) = 0.5 * (0.1+0.1) / 9.81 * cos(pi/3) * 0.1

(kg) = 0.5 * 0.2 / 9.81 * (1/2) * 0.1

(kg) =0.1 / 0.4905

(kg) = 0.2038kg.

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