Drop Force Calculator
Enter the values of initial momentum, Mi(kg.m/s), final momentum, Mf(kg.m/s) and time, t(s) to generate the value of Drop Force, Fd(N).
Drop Force Formula
Drop force refers to the force exerted over time to change an object’s momentum, typically from a higher to a lower value, effectively measuring the rate of this momentum change.
Drop force, Fd(N) in Newtons is equal to the change in momentum, which is the difference between the initial momentum, Mi(kg.m/s) in kilogram metre per second and the final momentum, Mf(kg.m/s) in kilogram metre per second divided by the time interval, t(s) in seconds over which the change occurs.
Drop force, Fd(N) = (Mi(kg.m/s) – Mf(kg.m/s)) / t(s)
Fd(N) = drop force in Newtons, N.
Mi(kg.m/s) = initial momentum in kilogram metre per second, kg.m/s.
Mf(kg.m/s) = final momentum in kilogram metre per second, kg.m/s.
t(s) = time in seconds, s.
Drop Force Calculation:
- A car of mass 1000 kg decelerates from 20 m/s to 0 m/s in 5 seconds. Calculate the drop force exerted by the car.
Given: Mi(kg.m/s) = 1000kg * 20 = 20000kg.m/s, Mf(kg.m/s) = 0kg.m/s, t(s) = 5s.
Drop force, Fd(N) = (Mi(kg.m/s) – Mf(kg.m/s)) / t(s)
Fd(N) = (20000 – 0) / 5
Fd(N) = 4000N.
- Suppose a hockey puck with an initial momentum of 30 kg·m/s comes to a final momentum of 10 kg·m/s. If the drop force exerted during this process is 5 N, find the time over which this change occurs.
Given: Mi(kg.m/s) = 30kg.m/s, Mf(kg.m/s) = 10kg.m/s, Fd(N) = 5N.
Drop force, Fd(N) = (Mi(kg.m/s) – Mf(kg.m/s)) / t(s)
t(s) = (Mi(kg.m/s) – Mf(kg.m/s)) / Fd(N)
t(s) = (30 – 10) / 5
t(s) = 4s.