Aluminium Square Hollow Tube Weight Calculator, Formula, Aluminium Square Hollow Tube Weight Calculation

Aluminium Square Hollow Tube Weight Calculator:

Enter the values of width, W_(cm), thickness of the tube, T_(cm) and Length, L_(cm) to determine the value of Weight, W_(g).

Aluminium Square Hollow Tube Weight Formula:

The physics of an aluminium square hollow tube’s weight revolves around the relationship between its structural geometry, material properties, and mass distribution.

The outer dimensions define the overall size of the tube, while the wall thickness specifies how much material exists between the hollow interior and the external surface.

This method reflects how the structural design minimizes weight without compromising the tube’s ability to bear loads. By using less material in a hollow structure, the tube maintains a balance between structural integrity and efficiency, making it both strong and lightweight.

The density of aluminium plays a crucial role in this calculation, as it directly influences the mass for a given volume of material.

Weight, W_(g) in grams equals the difference between the square of width, W_(cm) in centimetres and the square of the difference between width, W_(cm) and thickness of the tube, T_(cm) in centimetres all multiplied by Length, L_(cm) in centimetres and density of the acrylic material, d_(g/cm3) in grams per cubic centimetre.

Weight, W_(g) = [ W²_(cm) – (W_(cm)– T_(cm))² ] * L_(cm) * d_(g/cm3)

W_(g) = weight in grams, g.

W_(cm)= width in centimetres, cm.

T_(cm) = thickness of the tube in centimetres, cm.

L_(cm) = length in centimetres, cm.

d_(g/cm3) = density of the acrylic material in grams per cubic centimetre, g/cm³.

Acrylic Square Hollow Tube Weight Calculation:

1.An aluminium square hollow tube has a width of 6 cm, a thickness of 0.8 cm, a length of 150 cm, and the density of aluminium is 2.7 g/cm³. Calculate the weight of the tube.

Given:W_(cm)= 6cm, T_(cm) = 0.8cm, L_(cm) = 150cm, d_(g/cm3) = 2.7g/cm³.

Weight, W_(g) = [ W²_(cm) – (W_(cm)– T_(cm))² ] * L_(cm) * d_(g/cm3)

W_(g) = [6² – (6 – 0.8)²] * 150 * 2.7

W_(g) = 8.96 * 150 *2.7

W_(g) = 3628.8g.

2. An aluminium square hollow tube has a width of 8 cm, a wall thickness of 1 cm, a material density of 2.7 g/cm³, and it weighs 5184 g. Calculate the length of the tube.

Given:W_(cm)= 8cm, T_(cm) = 1cm, W_(g) = 5184g, d_(g/cm3) = 2.7g/cm³.

Weight, W_(g) = [ W²_(cm) – (W_(cm)– T_(cm))² ] * L_(cm) * d_(g/cm3)

L_(cm) = W_(g) / [ W²_(cm) – (W_(cm)– T_(cm))² ] * d_(g/cm3)

L_(cm) = 5184 / [64 – (49)] * 2.7

L_(cm) = 5184 / 40.5

L_(cm) = 128cm.