Acetal Round Hollow Tube Weight Calculator, Formula, Acetal Round Hollow Tube Weight Calculation

Acetal Round Hollow Tube Weight Calculator:

Enter the values of outer radii, R_(cm), inner radii, r_(cm) and tube’s length, L_(cm) to determine the value of weight of an acetal round hollow tube, W_(g).

Acetal Round Hollow Tube Weight Formula:

An Acetal round hollow tube is a cylindrical structural element made from Acetal, a thermoplastic polymer renowned for its high stiffness, dimensional stability, and low friction.

It is widely used in engineering applications due to its durability and resistance to wear, chemicals, and moisture. The tube features a hollow interior, which helps reduce the weight while maintaining structural strength.

The tube’s weight is determined by the volume of Acetal material used, which depends on its outer radius, inner radius, length, and density.

The outer and inner radii define the thickness of the tube walls, which is crucial for calculating the volume of material. The length of the tube and the density of Acetal further influence its overall weight.

The weight of an acetal round hollow tube, W_(g) in grams is calculated by multiplying the difference between the squares of the outer radii, R_(cm) in centimetres and inner radii, r_(cm) in centimetres by pi, then multiplying by the tube’s length, L_(cm) in centimetres and finally by the material’s density, d_(g/cm3) in grams per cubic centimetres.

Weight of an acetal round hollow tube, W_(g) = 3.14 * (R²_(cm) – r²_(cm)) * L_(cm) * d_(g/cm3)

W_(g) = weight of an acetal round hollow tube in grams, g.

R_(cm) = outer radii in centimetres, cm.

r_(cm) = inner radii in centimetres, cm.

L_(cm) = length in centimetres, cm.

d_(g/cm3) = density in grams per cubic centimetres, g/cm³.

Acetal Round Hollow Tube Weight Calculation:

1.An Acetal round hollow tube has an outer radius of 6 cm, an inner radius of 4 cm, a length of 150 cm, and the density of Acetal is 1.39 g/cm³. Calculate the weight of the tube.

Given: R_(cm) = 6cm, r_(cm) = 4cm, L_(cm) = 150cm, d_(g/cm3) = 1.39 g/cm³.

Weight of an ABS round hollow tube, W_(g) = 3.14 * (R²_(cm) – r²_(cm)) * L_(cm) * d_(g/cm3)

W_(g) = 3.14 * (6² – 4²) * 150 * 1.39

W_(g) = 3.14 * 20 * 150 * 1.39

W_(g) = 13093.8g.

2. An Acetal round hollow tube with an outer radius of 8 cm, an inner radius of 5 cm, and a density of 1.39 g/cm³ weighs 2,200 grams. Calculate the length of the tube.

Given: R_(cm) = 8cm, r_(cm) = 5cm, W_(g) = 2200g, d_(g/cm3) = 1.39 g/cm³.

Weight of an ABS round hollow tube, W_(g) = 3.14 * (R²_(cm) – r²_(cm)) * L_(cm) * d_(g/cm3)

L_(cm) = W_(g) / 3.14 * (R²_(cm) – r²_(cm)) * d_(g/cm3)

L_(cm) = 2200 / 3.14 * (8² – 5²) * 1.39

L_(cm) = 12.89cm.