Acetal C Channel Weight Calculator:
Enter the values of width, W(cm), flange thickness, T1(cm), height, H(cm), web thickness, T2(cm) and length, L(cm) to determine the value of weight of an acetal C channel, W(g).
Acetal C Channel Weight Formula:
Acetal, also known as polyoxymethylene (POM), is a thermoplastic polymer known for its high strength, stiffness, low friction, and excellent dimensional stability.
The C channel refers to the shape of the cross-section of the material, which resembles the letter “C”. This shape provides the channel with a high strength-to-weight ratio, making it both robust and lightweight.
The open side of the “C” allows for easy attachment or accommodation of other components, making it versatile in applications such as guides, tracks, supports, and frameworks.
Acetal’s resistance to temperature changes ensures that the C-channel maintains its shape and size, providing reliable performance in varying environmental conditions.
The weight of an acetal C channel, W(g) in grams is the sum of twice the product of the width, W(cm) in centimetres and thickness of the width walls, T1(cm) in centimetres, plus the product of the height, H(cm) in centimetres and thickness of the height wall, T2(cm) in centimetres, all multiplied by the length, L(cm) in centimetres and the material density, d(g/cm3) in grams per cubic centimetres.
Weight of an acetal C channel, W(g) = (2 * W(cm) * T1(cm) + H(cm) * T2(cm)) * L(cm) * d(g/cm3)
W(g) = weight in grams, g.
W(cm) = width in centimetres, cm.
T1(cm) = thickness of the width walls in centimetres, cm.
T2(cm) = thickness of the height wall in centimetres, cm.
H(cm) = height in centimetres, cm.
L(cm) = length in centimetres, cm.
d(g/cm3) = density in grams per cubic centimetres, g/cm3.
Acetal C Channel Weight Calculation:
- An Acetal C channel has a width (W) of 4 cm, height (H) of 3 cm, wall thicknesses (T1) of 0.5 cm, (T2) of 0.5 cm, length (L) of 150 cm, and a material density (d) of 1.41 g/cm³. Calculate the weight of the channel.
Given: W(cm) = 4cm, T1(cm) = 0.5cm, T2(cm) = 0.5cm, L(cm) = 150cm, H(cm) = 3cm,
d(g/cm3) = 1.41g/cm3.
Weight of an acetal C channel, W(g) = (2 * W(cm) * T1(cm) + H(cm) * T2(cm)) * L(cm) * d(g/cm3)
W(g) = (2 * 4 * 0.5 + 3 * 0.5) * 150 * 1.41
W(g) = (4 * 1.5) * 150 * 1.041
W(g) = 5.5 * 150 *1.41
W(g) = 1163.25g.
- An Acetal C channel has a width (W) of 6 cm, height (H) of 4 cm, wall thicknesses (T1) of 0.3 cm, (T2) of 0.4 cm, and a material density (d) of 1.41 g/cm³. The channel weighs 847.2 g. Calculate the length (L) of the channel.
Given: W(cm) = 6cm, T1(cm) = 0.3cm, T2(cm) = 0.4cm, W(g) = 847.2g, H(cm) = 4cm,
d(g/cm3) = 1.41g/cm3.
Weight of an acetal C channel, W(g) = (2 * W(cm) * T1(cm) + H(cm) * T2(cm)) * L(cm) * d(g/cm3)
L(cm) = W(g) / (2 * W(cm) * T1(cm) + H(cm) * T2(cm)) * d(g/cm3)
L(cm) = 847.2 / (2 * 6 * 0.3 + 4 * 0.4) * 1.41
L(cm) = 847.2 / 7.352
L(cm) = 115.2cm.